Electronic configuration of Zn : [Ar] 4s2 3d10
the last electron is added in 3d
so n = principal quantum number hence n = 3 (for last electron)
orbital is d hence l = 2
m will have values from -l to +l hence it will be between -2 to + 2 so from the option it is +2
andd spin of last electron will be down hence s = -1/2
so for the last electron OPTION 3 IS CORRECT
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