Question

of Acids and Bases e three ways in which to define acids and bases: the Arrhenius concept, the Bronsted-Lowry concept, and the Lewis cc d in water, increase the concentration of the H ion; Arrhenius bases are substances that, when dissolved in water, inc e substances that can donate a proton (H) to another substance; Bronsted-Lowry bases are substances that can acce r, and a Lewis base is an electron-pair donor. Part A Using the Arrhenius concept of acids and bases, identify the Arrhenius acid and base in each of the following reactions: 2KOH(aq)+ H2S0 (aq) K,SO4 (aq)+2H3O() NH3 (8)+ HCl(g)NH,Cl(s) Drag the appropriate Items to their respective bins. View Avalable Hint(s) КОН Н,SO, NHs НСI Arrhenius acid Arrhenius base Neit PPearson Copyright o 2019 Pearson Education Inc. All rights reserved. I Ierms of Use I Privacy Policy go F3 F4 E5 F6 E7

Answer 1

Arrhenius acid: Arrhenius acid is a substance that dissociates in water and gives H⁺ ion(Proton).

example: HCl(aq) $\rightarrow$ H⁺(aq) + Cl^-(aq)

Here HCl act as Arrhenius acid

Arrhenius base: Arrhenius base is a substance that dissociates in water and gives OH^-ion.

example: NaOH(aq)   $\rightarrow$ Na⁺(aq) + OH^-(aq)

Here NaOH act as a Arrhenius base.

The given reaction reaction

2KOH(aq) + H₂SO₄(aq) $\rightarrow$ K₂SO₄ (aq) + 2H₂O(l)

here KOH dissociates as

2KOH(aq) $\rightarrow$ 2K⁺(aq) + 2OH^-(aq)

and H2SO4 dissociates as

H₂SO₄(aq) $\rightarrow$ 2H⁺(aq) + SO₄²-(aq)

And the products are formed by

2K⁺(aq) + 2OH^-(aq) +2H⁺(aq) + SO₄^2-(aq) $\rightarrow$ K₂SO₄(aq) + 2H₂O(l)

Now we can conclude that in this reaction KOH act as Arrhenius base and H₂SO₄ as Arrhenius acid

next

NH₃(g) + HCl(g) $\rightarrow$ NH₄Cl

here, both the reactant is in gas phase

if we use water as solvent then

HCl(aq) $\rightarrow$ H⁺(aq) + Cl^-(aq)

and

NH₃(aq) + H^₊(aq) + Cl $\rightarrow$ NH₄⁺ + Cl^-(aq)

in aquous slolution NH₄Cl remain as NH₄⁺ and cl^- . In solid phase it stays as NH₄Cl

Here HCl act as Arrhenius ase but NH3 is not acting as arrhenius base or acid.

Since it accepting a proton so it act as Bronsted base.