Please show all steps taken (prefer typed solution)
| Half-Reaction | E
° (V) |
| Ag+ (aq) + e− → Ag (s) | 0.7996 |
| Al3+ (aq) + 3e− → Al (s) | −1.676 |
| Au+ (aq) + e− → Au (s) | 1.692 |
| Au3+ (aq) + 3e− → Au (s) | 1.498 |
| Ba2+ (aq) + 2e− → Ba (s) | −2.912 |
| Br2 (l) + 2e− → 2Br− (aq) | 1.066 |
| Ca2+ (aq) + 2e− → Ca (s) | −2.868 |
| Cl2 (g) + 2e− → 2Cl− (aq) | 1.35827 |
| Co2+ (aq) + 2e− → Co (s) | −0.28 |
| Co3+ (aq) + e− → Co2+ (aq) | 1.92 |
| Cr2+ (aq) + 2e− → Cr (s) | −0.913 |
| Cr3+ (aq) + 3e− → Cr (s) | −0.744 |
| Cr3+ (aq) + e− → Cr2+ (aq) | −0.407 |
| CrO42− (aq) + 4H2O (l) + 3e− → Cr(OH)3 (s) + 5OH− (aq) | −0.13 |
| Cu2+ (aq) + 2e− → Cu (s) | 0.3419 |
| Cu2+ (aq) + e− → Cu+ (aq) | 0.153 |
| Cu+ (aq) + e− → Cu (s) | 0.521 |
| F2 (g) + 2e− → 2F− (aq) | 2.866 |
| Fe2+ (aq) + 2e− → Fe (s) | −0.447 |
| Fe3+ (aq) + e− → Fe2+ (aq) | 0.771 |
| Fe3+ (aq) + 3e− → Fe (s) | −0.037 |
| 2H+ (aq) + 2e− → H2 (g) | 0.000 |
| 2H2O (l) + 2e− → H2 (g) + 2OH− (aq) | −0.8277 |
| H2O2 (aq) + 2H+ (aq) + 2e− → 2H2O (l) | 1.776 |
| I2 (s) + 2e− → 2I− (aq) | 0.5355 |
| 2IO3− (aq) + 12H+ (aq) + 10e− → I2 (s) + 6H2O (l) | 1.195 |
| Mg2+ (aq) + 2e− → Mg (s) | −2.372 |
| Mn2+ (aq) + 2e− → Mn (s) | −1.185 |
| MnO2 (s) + 4H+ (aq) + 2e− → Mn2+ (aq) + 2H2O (l) | 1.224 |
| MnO4− (aq) + 8H+ (aq) + 5e− → Mn2+ (aq) + 4H2O (l) | 1.507 |
| MnO4− (aq) + 2H2O (l) + 3e− → MnO2 (s) + 4OH− (aq) | 0.595 |
| HNO2 (aq) + H+ (aq) + e− → NO (g) + H2O (l) | 0.983 |
| N2 (g) + 4H2O (l) + 4e− → 4OH− (aq) + N2H4 (aq) | −1.16 |
| NO3− (aq) + 4H+ (aq) + 3e− → NO (g) + 2H2O (l) | 0.957 |
| Na+ (aq) + e− → Na (s) | −2.71 |
| Ni2+ (aq) + 2e− → Ni (s) | −0.257 |
| O2 (g) + 4H+ (aq) + 4e− → 2H2O (l) | 1.229 |
| O2 (g) + 2H2O (l) + 4e− → 4OH− (aq) | 0.401 |
| O2 (g) + 2H+ (aq) + 2e− → H2O2 (aq) | 0.695 |
| Pb2+ (aq) + 2e− → Pb (s) | −0.1262 |
| PbSO4 (s) + H+ (aq) + 2e− → Pb (s) + HSO4− (aq) | −0.3588 |
| HSO4− (aq) + 3H+ (aq) + 2e− → H2SO3 (aq) + H2O (l) | 0.172 |
| Sc3+ (aq) + 3e− → Sc (s) | −2.077 |
| Sn2+ (aq) + 2e− → Sn (s) | −0.1375 |
| Sn4+ (aq) + 2e− → Sn2+ (aq) | 0.151 |
| VO2+ (aq) + 2H+ (aq) + e− → VO2+ (aq) + H2O (l) | 0.991 |
| Zn2+ (aq) + 2e− → Zn (s) | −0.7618 |
Homework Answers
E0cell = E0cathode - E0anode
given cell required volts E0cell = +0.80 V, and E0anode = -0.35 V
E0cathode = E0cell + E0anode = +0.80 V + (-0.35 V) = +0.45 V
E0cathode = +0.45 V
So at least a minimum of +0.45 V must be supplied by cathode to achieve 0.80 V, and there is no maximum limit since they asked us at least 0.80 V should be supplied.
we can use any reaction that has minimum +0.45 V
Hope this helped you!
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Please show all steps taken (prefer typed solution)
Half-Reaction
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2. If im asked for the best reducing agent from Cu+, Ag+, F2, and
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3. Sometimes a value that has originally a positive (V) from the
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