Question

5. Consider the following balanced equation and answer parts (a) through (g). Show calculations for each part. 3 Ag(s) + 4HNO
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Answer #1

a)

As per the stoichiometric equation, 3 moles of Silver reacts with excess nitric acid forms 3 moles of silver nitrate.

3.10 moles of silver on reaction with excess of nitric acid forms 3.10 moles of silver nitrate.

b)

3*107.8682 grams of silver on reaction with excess of nitric acid forms 3 moles of silver nitrate.

108.21 grams on reaction with excess of nitric acid forms

how many moles silver nitrate

= 108.21*3/3*107.8682

= 0.9908 moles of silver nitrate is formed.

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