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BACK NEXT Chapter 17, Problem 050 GO A tube 1.30 m long is closed at one end. A stretched wire is placed near the open end. T
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Answer #1

A)

Frequency, f = v/4L

f = 340/(4 x 1.3) = 65.38 Hz

B)

Linear density, u = 0.0097/0.351 = 0.0276 kg/m

Frequency, f = (1/2L) sqrt(T/u)

65.38 = (1/2 x 0.351) sqrt(T/0.0276)

Tension, T = 58.15 N

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