Homework Answers
R2 and R3 are in parallel
R = R2R3 / (R2 + R3)
= 4.7*6.2 / ( 4.7 + 6.2)
= 2.67 ohm
R1 and R are in series
R(equi) = R1 + R = 2.2 + 2.67 = 4.87 ohm
current I through the circuit = V/R = 79/4.87 = 16.21 A
current through R3 = 16.21 - 6.3 = 9.91 A
the device would be absorbing the energy at the rate = I^2*R3 = 9.91^2*6.2 = 608.94 W
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