Andrea Deposits $1000 into a savings account today. The annual interest rate is 10%, but compounds semi-annually. How many years will it take for her money to grow to $4,356,561?
future amount = amount deposited*(1+r)^n
here,
future amount = 4356561
amount deposited =1000
interest rate = 10% per annum =>10*6/12=>5% for semi annual period =>0.05
n = total number of semi annual periods = to be found out.
=>1000*(1+0.05)^n=4356561
=>(1.05)^n=4,356.561.
apply logarithms on both sides.
=> n log (1.05) = log (4356.561)
=>n*0.0211893 =3.6391438
=>n=171.744409..........(these are semi annual periods)
so number of years = 171.744409 / 2 semi annual periods per year
=>85.87 years.or 86 years to round off.
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