Question

An airplane climbs at an angle of 15 degrees with a horizontal component of speed of 200 km/h. A) what is the planes actual speed? B) what is the magnitude of the vertical component of its velocity?

Answer 1

Horizontal Component of velocity,
$v_{x} = v*cos\theta$

$v= \frac{v_{x}}{cos\theta }$

$v= \frac{200}{cos15 }$

$v=207.055 kmph$

B)

Vertical component
$tan\theta = \frac{v_{y}}{v_{x}}$

$tan15 = \frac{v_{y}}{200}$

$v_{y}=53.589 kmph$