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Important instructions: For all situations requiring a hypothesis test (z test, one-samplet test, one-sample variance test or
2. *(10 points) These data are not normal, so you will need to apply the appropriate two-sample test for non-normal data. You
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Answer #1

1) two sample t test with equal variance

2)

Ho :   µ1 - µ2 =   0
Ha :   µ1-µ2 ╪   0

3) two tail test, because alternative hypothesis is non directional

4) Sample #1   ---->   1                  
mean of sample 1,    x̅1=   5.590                  
standard deviation of sample 1,   s1 =    0.742                  
size of sample 1,    n1=   10                  
                          
Sample #2   ---->   2                  
mean of sample 2,    x̅2=   4.411                  
standard deviation of sample 2,   s2 =    1.034                  
size of sample 2,    n2=   9                  
                          
difference in sample means =    x̅1-x̅2 =    5.5900   -   4.4   =   1.179  
                          
pooled std dev , Sp=   √([(n1 - 1)s1² + (n2 - 1)s2²]/(n1+n2-2)) =    0.8911                  
std error , SE =    Sp*√(1/n1+1/n2) =    0.4094                  
                          
t-statistic = ((x̅1-x̅2)-µd)/SE = (   1.1789   -   0   ) /    0.41 =   2.8794

5)

Degree of freedom, DF=   n1+n2-2 =    17  
p-value =        0.010406 (excel function: =T.DIST.2T(t stat,df) )
Conclusion:     p-value <α , Reject null hypothesis     

There is enough evidence that two breeds differ in sensitivity at α=0.05

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