Solution) V = 24 v
R = 5 ohm
L = 2.4 H
(a) Energy stored in inductor when current reaches maximum value , U = ?
U = (1/2)(L)(i^2)
i = V/R
i = (24)/(5)
i = 4.8 A
U = (1/2)(2.4)(4.8^2)
U = 27.6 J
(b) Energy stored after one time constant , U' = ?
i' = i( 1 - e^(-t/T))
Here t = T
i' = i(1 - e^(-T/T))
i' = i(1 - e^(-1))
i' = 4.8( 1 - e^(-1))
i' = 3.03 A
U' = (1/2)(L)(i'^2)
U' = (1/2)(2.4)(3.03^2)
U' = 11 J
4. + -12 points SerCP11 20.7.P.051.MI. A 24-V battery is connected in series with a resistor...
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