Two small nonconducting spheres have a total charge of 94.0 μC . When placed 1.11 m apart, the force each exerts on the other is 11.5 N and is repulsive. What is the charge on each?
What if the force were attractive?
a) for repulsive force
q1 + q2 = 94
F = k q1 q2 / r^2
11.5 = 9*10^9*10^-12* ( 94 - q2) q2 / 1.11^2
-q2^2 + 94 q2 - 1574.35 = 0
solving for q2
q2 = 21.8 uC
q1 = 72.2 uC
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for attractive
q1 - q2 = 94
11.5 = 9*10^9*10^-12 * ( 94 + q2) q2 / 1.11^2
q2^2 + 94 q2 - 1574.35 = 0
q2 = 14.51 uC
q1 = 108.51 uC
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Comment in case any doubt, will reply for sure. Goodluck
Two small nonconducting spheres have a total charge of 94.0 μC . When placed 1.11 m...
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