Question

Two facing surfaces of two large parallel conducting plates separated by 12.0 cm have uniform surface charge densities such that are equal in magnitude but opposite in sign. The difference in potential between the plates is 490 V. (a) Is the positive or the negative plate at the higher potential? O the pusitive plale O the negative plate (b) What is the magnitude of the electric field between the plates? kV/m (c) An electron is released from rest next to the negatively charged surface. Find the wark done by the electric tield on the electron as the electron moves from the release point to the positive plate Express your answer in both electron volts and joules. (d) What is the change in potentlal energy of the electron when It moves from the release point to the posltlve plate? (e) What is its kinetic energy when it reaches the positive plate? ev eBook

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Answer #1

Solution) The electric field E = dV/dr

W=qdV

Ca) the foue plare at higher poTetil r Twe blate eahic ブ 12x10 C) Work done, cw-? We 4oev ency

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