A skier of mass 50.9 kilograms is racing down a hill with an angle of incline...
A skier of mass 50.9 kilograms is racing down a hill with an angle of incline of 20.1 degrees. Ignore air resistance and all other types of friction. Yes, I know that is silly. Wait for the next question. What is the acceleration in metres per second squared of the skier?
Homework Answers
Given,
m = 50.9 kg ; theta = 20.1 deg
We know when there is no friction, the acceleration of mass on an inclined plane is given by:
a = g sin(theta)
a = 9.8 sin20.1 = 3.37 m/s^2
Hence, a = 3.37 m/s^2
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