A person throws 3 dice. Which of the events A or B is more likely where...

Question

Question

A person throws 3 dice. Which of the events A or B is more likely where Aeach die shows an odd number B - the sum of the 3 numbers is divisible by 9

Answer 1

Answer #1

When 3 dice are thrown, there are 216 outcomes

(a) A = {111, 113, 115, 131, 133, 135, 151, 153, 155, 311, 313, 315, 331, 333, 335, 351, 353, 355, 511, 513, 515, 531, 533, 535, 551, 553, 555}

n(A) = 27

P(A) = 27/216

(b) The following outcomes give a sum divisible by 9

n(B) = 26

P(B) = 26/216

Thus, event A is more likely.

Answer 2

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