1)
Given:
P = 715.2 torr
= (715.2/760) atm
= 0.9411 atm
V = 18.6 L
T = 146.8 oC
= (146.8+273) K
= 419.8 K
find number of moles using:
P * V = n*R*T
0.9411 atm * 18.6 L = n * 0.08206 atm.L/mol.K * 419.8 K
n = 0.5081 mol
use:
number of molecules = number of mol * Avogadro’s number
number of molecules = 0.5081 * 6.022*10^23 molecules
number of molecules = 3.06*10^23 molecules
Answer: 3.06E23 molecules
Only 1 question at a time please
QUESTION 1 A sample of nitrogen gas is sealed into a 18.6 L container at 715.2...
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QUESTION 2 A sample of nitrogen gas is sealed into a 18.6 L container at 715.2 torr and 146.8 °C. How many nitrogen molecules are in the container? (Enter your value in E-notation with three significant figures.]
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