Question

u ul 11 J00 and 14 500 cm . 20.12 The 3p% configuration of an Si atom gives rise to the following terms: 'So, 'P2, P1, 'Po and 'D2. Use Hund's rules to predict the relative energies of these terms, giving an explanation for your answer.

Answer 1

Sul 20.12 a spin multiplicity. - Term Term Symbal = 2511? Sym → For energy is that a given which has configuration, highest spin term of lowest multiplicity. is term of lowest cravgy > 1 If with two terms have highest value of some l will spin multiplicity, state be . term of lowest - valve af L. energy. . 1 q is lower in energy than 2 - LD 1. 9f both spin multiplicities and values of i are same, .. then state with lowegst I value will be of . lowest energy when subshell is less them half tilled. si is less than halt tilled energy {ground 3p is term with lowest state term.). energy ® os value of 0 h. 3P6 < 3p, 23P 2 <40, <15. i 3p in energy. As they have highest spin is lowest multiplicity