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A buffer solution contains 0.64 mol of hydrocyanic acid (HCN) and 0.59 mol of sodium cyanide...

A buffer solution contains 0.64 mol of hydrocyanic acid (HCN) and 0.59 mol of sodium cyanide (NaCN) in 5.10 L.
The Ka of hydrocyanic acid (HCN) is Ka = 4.9e-10.


(a) What is the pH of this buffer?

pH = 9.345


(b) What is the pH of the buffer after the addition of 0.44 mol of NaOH? (assume no volume change)

pH =


(c) What is the pH of the original buffer after the addition of 0.25 mol of HI? (assume no volume change)

pH =

I got part (a) correct, I just cannot figure out the other two

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Answer #1

(6) Addition of 0.44 mol of Nach Now, nach realt with HIN, Nould then nach + H₂O Morce NaN will be formed. So, 10 of moles of(e) Addition of Ongs mal of HI HI & NON HON + N +1- More HON will form so No. of moles of 4CN = 0.25 +0.69. = 0.samole No. of

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