Question

In a mixture solution containing equal masses of oxygen and nitrogen gasses, the total pressure is 750 mmHg. What is the partial pressure of nitrogen in the mixture?

Answer 1

Molar mass of oxygen = 32 g/mol

Molar mass of nitrogen = 28 g/mol

Let the mixture contains 109 of each gas. Number of moles= Mass (g) et dont l-lu Molar mass (g/mol) Moles of N₂ = 10. Moles of O₂ = 10 0.36 mol = 0.31 mol- 32 28 Mole fraction - Moles Total Moles B Mole fraction of N₂ = 0.363 0. 0.36 + 0.31 - 0.54 Partial pressure - Total b y Mole pressure fraction Partial Pressure of N, = 750x 0.54 » 405 mm Hg