Question

Question 10 1 pts Consider the Lewis structure of Br4 , what is the bond angle between Br-1-Br? = 90° = 120° < 120° < 90° < 109.50 Consider the Lewis structure of CIO3 , what is the bond angle between C-O-CI? = 120° < 120° = 180° < 109.50 = 109.50

Answer 1

$No. Of electron pair around Central atom is given by= \frac{V+M-C+A}{2}$

Where V=No. Of valence electrons around Central atom

M=monovalent atoms

C=Positive charge

A=negative charge

In IBr4- above fomula gives 6 electron pair around iodine. It gives octahedral geometry in which 4 are bond pair and two lone pairs. Lone pairs are arranged at 180 degree to each other. Br-I-Br angle is 90 degrees.

In ClO3- above formula gives 4 electron pair out of which three are bond pair and one lone pair. O-Cl-O angle will be less than tetrahedral angle(109.5 degree) due to strong bond pair-lone pair repulsion which dominates over bond pair- bond pair repulsion.