Question

The Kow of 1,2,4-trichlorobenzene is 104 (mol/L octanol)/(mol/L water), and the Henry's law constant K is 0.112 mol L-1 atm-. If you have 1 L of water, 500 mL of octanol and 100 mL of air in a sealed flask, what fraction of the 1,2,4-trichlorobenzene will be in the aqueous phase? Notes: (1) The mass of 1,2,4-trichlorobenzene in phase j is M, C x Vj, where C is concentration and V is volume. Total 1,2,4-trichlorobenzene mass = (2) Kow Coct/Cwater (3) K Cwater/P. ΣΜ.

Answer 1

I sol; - Let is consides KH = water P water = klop.. KH = 00112 Mlalom. = 0: 112 x 1 = 0.112 mol. Lilé?. of 1,2,4-trichlorobenzene in aqueous phase. I. Mass co - Cag x Var. - 0.112 x 12 = 0.02 moles Kwa Coct . - Gwater Cort & Kwx (water = 104 x 0.112 = 1/2 x 103 moll'. mass of 1,2,4-trichloso benzene an octanol Phase = Coct x V och = 1.12 x 10° x0.5 = 5.6x10? moli? Fraction of 1,2,4-trichlorobenzene an aqueous Phase 0.112 5.6x102 = 2x104.