4) Blue light (440 nm) shines on water (n-1.33) that has a thin layer of oil...

Question

Question

Answer 1

Answer #1

for constructive interference we write

2µd = (m+½)λ

where µ is the refractive index of thin film (here oil µ = 1.10)

for minimum thickness m = 0

so 2µd = λ/2

d = λ/(4µ) = (440 x 10^-9) / (4 x 1.10)

d = 1 x 10^-7

d = 10 x 10^-6 m

d = 10 µm <<<<<< Answer

Answer 2

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