Question

3. The Ksp for silver chloride is 1.8 x 10-10 at 25 °C. What is the solubility of silver chloride (in mol L?) in 0.025 M tin

0 0
Add a comment Improve this question Transcribed image text
Answer #1

3)

SnCl4 here is Strong electrolyte

It will dissociate completely to give [Cl-] = 4*[SnCl4]

= 4*0.025 M

= 0.1 M

At equilibrium:

AgCl <----> Ag+ + Cl-

   s 0.1 + s

Ksp = [Ag+][Cl-]

1.8*10^-10=(s)*(0.1+ s)

Since Ksp is small, s can be ignored as compared to 0.1

Above expression thus becomes:

1.8*10^-10=(s)*(0.1)

s = 1.8*10^-9 M

Answer: d

Only 1 question at a time please

Add a comment
Know the answer?
Add Answer to:
3. The Ksp for silver chloride is 1.8 x 10-10 at 25 °C. What is the...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT