Question

A simple pendulum of mass 0.2 kg and length 0.4 m oscillates freely.

At the end of its swing (point B), it has 0.45 J of gravitational potential energy with respect to its lowest point.

Determine the total mechanical energy of the pendulum when it is halfway in height (point A) between its lowest point and the end of its swing.

Show your calculations/explain your reasoning.

В A lowest point

Answer 1

- - - - A Lowest point At the lowet boint Gravitational potential energy is to we takes lowest point as reference At the lowest point kinetic energy is manimum at mer Total mechanical energy = h mua At the nighest boint B. - kinetic energy ao As veo at Bi potential energy a ngon na height of B. wirt lowest point with respect to mghe +0.45 S rotal energy of B=KETPE +0.45 20,453 0 cs Scanned with CamScanner

At 'A Gravintadional - man = myn KE = £ mah * Total energy Imrat e as = 0.457 As energy is conserved. .. Energy, aut B = Energy at :: Ķmat 0.45 20:45 z mua 0.45*2 ܗ sܦ.ܘ .ܝ 19.45 = 1.5 mis. - mechanical Totalrenergy ad A 0.45 CS Scann Scanned with CamScanner