8)
X =poisson with lambda = 5/hour
a) for one hour
= 5
P(X =8)
=e^(-5) * 5^8 /8!
= 0.065278
b)
P(X <= 3)
= P(X =0) + P(X = 1) + P(X = 2) + P(X = 3)
= 0.26503
c)
for two hours
= 5*2 = 10
P(X = 12) =
0.09478
d)
for 30 minutes
= 5/2 = 2.5
P(X =4) = 0.1336
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