Question

2. (8 points) Let F- try - vy2. Evaluate the line integralF dl using the f ollowing paths: a) (2 points) Going from 0, 0 to r 2,y 1 along the straight line y b) (2 points) Going from 0, 0 to r 2,y-1 along the parabola y c) (2 points) Going from 0,y 0 to 2,y 1 by going first along a vertical line from0,y0 to x-0, y-l then along the horizontal line x , y-i to x-2, y-1, d) (2 points) Going from 0,y to 2,y 1 ing the path (z(t), y()) where () 2t3,y)
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Given,

overrightarrow{F} = hat{x}xy-hat{y}y^{2} .................................(1)

and,

I = int overrightarrow{F}.overrightarrow{dl}

or,   I = int left ( hat{x}xy-hat{y}y^{2} ight ).left ( hat{x}dx+hat{y}dy+hat{z}dz ight )

or, I = int xydx-y^{2}dy ....................................(2)

(a) Given,

y= rac{1}{2}x

or,   2 dy =-dr

And the range of x is from x= 0 to x = 2 .

Putting all the values in equation (2), we get

2 0

or,   0 3-8

or, I = rac{3}{8} left [ rac{x^{3}}{3} ight ]_{0} ^{2}

or,   5

or, I = 1

(b)  Given,

  14

so,   2 dy =-xdr

and the range of x is from x = 0 to x = 2.

Putting all the values in equation (2), we get

  2 2 2 0

or, 0

or, 16 32 6 5

or,   I = left [ 1 - rac{1}{3} ight ]

or,   I =rac{2}{3}

(c)  In this case, the integration is along the two paths : first along a vertical line from y = 0 (x= 0) to y = 1(x = 0) (i.e. along y - axis) and then along a horizontal line from x= 0 (y = 1) to x = 2 (y = 1) (i.e. parallel to the x - axis).

Let's denote the first path (i.e. along the y - axis) by 'A' and the second path (i.e. parallel to x -axis) by 'B' .

Integral along the path A :

The equation of the line (path of integration) will be , x = 0.

So, dx = 0

So, the integration will be

I_{A} =int_{0}^{1} 0- y^{2}dy

or, ム=- y dy

or, 3 2

or, I_{A} = - rac{1}{3}

Integral along the path B :

The equation of the line(path of integration) will be : y = 1 .

So, dy = 0

So, the integration will be

I_{B} = int_{0}^{2}left [ xdx - 0 ight ]

or, I_{B} = int_{0}^{2}xdx

or, I_{B} = left [ rac{x^{2}}{2} ight ] _{0} ^{2}

or,  I_{B} = 2

Hence the final result will be

I = I_{A}+I_{B}

or, I = - rac{1}{3} + 2 = rac{5}{3}

(d)  Given,

  x= 2t^{3} and y =t^{2}

So,   dx = 6 t^{2} dt and dy = 2tdt

And, for x = 0 ; t = 0 and for x = 2 ; t = 1 this condition (or limits) is also satisfied for y = 0 and y =1 .

So, I = int_{0}^{1} left [ 2t^{3} imes t^{2} imes 6t^{2}dt - left ( t^{2} ight )^{2} imes 2t dt ight ]

or,   I = int_{0}^{1} left [ 12t^{7} dt - 2 t^{5} dt ight ].

or,   I = left [ 12 , imes rac{t^{8}}{8} - 2 imes rac{t^{6}}{6} ight ]_{0} ^{1}

or, I = left [ 12 , imes rac{1}{8} - 2 imes rac{1}{6} ight ]

or, I = left [ rac{3}{2} - rac{1}{3} ight ]

or, I = rac{7}{6}

For any doubt please comment and please give an up vote. Thank you.  

Add a comment
Know the answer?
Add Answer to:
2. (8 points) Let F- try - vy2. Evaluate the line integralF dl using the f...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT