Question

Free Energy and Equlibrium Consider the system: A(g) = B(9) at 25°C. Assume that GºA = 8334 J/mol and GºB = 11324 J/mol. Calc

0 0
Add a comment Improve this question Transcribed image text
Answer #1

page: or Answen: According to the given Question, to find the following problems. Giveni GPA = 8334 3lmol GB = 11324 J/mol AGpageto2 2990J/mol = - (8.3143|molx x 298X ) In Kp 2990 - - 2475.59 loko In kp --- 2990 2497:52 In Kp = -1.2068 Kpse-12068 KPpage:03 Kp = 12 14x 0.315 1-X 1+x 0.315(1+2) : 1-2 0.315 +0.3156 1-2 0.315+0.315XX L 0.315+ 1.3154 all 1:3157 2.1-0.315 1:31Spage:ou * partial pressure of B(9) Ps: PB = (1-2) atm 1-0.52) atm PB 0.uta atm in partial pressure of Bigg = 0.479 atm.

Add a comment
Know the answer?
Add Answer to:
Free Energy and Equlibrium Consider the system: A(g) = B(9) at 25°C. Assume that GºA =...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Free Energy and Equlibrium Consider the system: A(g) = B(9) at 25°C. Assume that GºA =...

    Free Energy and Equlibrium Consider the system: A(g) = B(9) at 25°C. Assume that GºA = 7012 J/mol and GºB = 12316 J/mol. Calculate the value of the equilibrium constant for this reaction. 1 pts Submit Answer Tries 0/5 A non-equilibrium mixture of 1.00 mol of A(g) (partial pressure 1.00 atm) and 1.00 mol of B(g) (partial pressure 1.00 atm) is allowed to equilibrate at 25°C. Calculate the partial pressure of A(9) at equilibrium. 1pts Submit Answer Tries 0/5 Calculate...

  • Please show work step by step and final answer. Free Energy and Equlibrium Consider the system:...

    Please show work step by step and final answer. Free Energy and Equlibrium Consider the system: A(9) = B(9) at 25°C. Assume that GºA = 7082 J/mol and GºB = 12192 J/mol. Calculate the value of the equilibrium constant for this reaction. 1.27x10-1 1pts You are correct. Previous Tries A non-equilibrium mixture of 1.00 mol of A(9) (partial pressure 1.00 atm) and 1.00 mol of B(9) (partial pressure 1.00 atm) is allowed to equilibrate at 25°C. Calculate the partial pressure...

  • Heat Capacity of a Gas at Constant Pressure A system comprised of 5.500x101 g of Ar(g)...

    Heat Capacity of a Gas at Constant Pressure A system comprised of 5.500x101 g of Ar(g) cools from 165.0°C to 30.0°C at a constant pressure of 3.0 atm. The molar heat capacity at constant pressure for Ar(g) is 20.80 J K-1 mol-1. Calculate q. 1pts Submit Answer Tries 0/5 Calculate w 1pts Submit Answer Tries 0/5 Calculate ΔΕ. 1 pts Submit Answer Tries 0/5 Calculate ΔΗ. 1pts Submit Answer Tries 0/5

  • Need work step by step please! Heat Capacity of a Gas at Constant Pressure A system...

    Need work step by step please! Heat Capacity of a Gas at Constant Pressure A system comprised of 1.900x100 g of C2H6(9) cools from 180.0°C to 45.0°C at a constant pressure of 2.5 atm. The molar heat capacity at constant pressure for C2H6(9) is 52.92 J K-1 mol-1. Calculate q. 1 pts Submit Answer Tries 0/5 Calculate w. 1 pts Submit Answer Tries 0/5 Calculate ΔΕ. 1pts Submit Answer Tries 0/5 Calculate ΔΗ. 1pts Submit Answer Tries 0/5

  • Free Energy of Reaction -- Temperature Dependence eu. 1000°C 2NH3(g) + 302(g) + 2CH4(9) DIDA →...

    Free Energy of Reaction -- Temperature Dependence eu. 1000°C 2NH3(g) + 302(g) + 2CH4(9) DIDA → 2HCN(9) + 6H20(9) The above reaction is used in the industrial production of hydrogen cyanide. Consider the relevant thermodynamic data from the appendices of your text. (The tabulated values AHºf and sº are for 25°C. For the purposes of this question assume that AH° and ASº are invariant with temperature. This is not actually true but would generally be a reasonable approximation over "small"...

  • Dalton's Law of Partial Pressures I (two parts) For a mixture of three gases, consisting of...

    Dalton's Law of Partial Pressures I (two parts) For a mixture of three gases, consisting of an equal number of moles of Xe, Kr, and CF4, at a total pressure of 4.50 atm, what is the partial pressure of Xe? 2pts (Submit Answer Tries 0/5 For a mixture of two gases, consisting of 1.00 mol of X and 1.00 mol of H2, at a total pressure is 4.50 atm, what is the partial pressure of Xe? 2pts ( Submit Answer)...

  • need help, the answer is suppose to be PA=0.136 atm PB=0.136 atm PC=1.73 atm 13. Consider the reaction A(g)B(g) >2 C (g) Where. DH -15.62 kJ/mol Ds -10.20 J/mol K (a) Suppose that a tank is fil...

    need help, the answer is suppose to be PA=0.136 atm PB=0.136 atm PC=1.73 atm 13. Consider the reaction A(g)B(g) >2 C (g) Where. DH -15.62 kJ/mol Ds -10.20 J/mol K (a) Suppose that a tank is filled with A (g) and B (g) such that P 1.00 atm and P, 1.00 atm at a temperature of 25.0'C. Calculate the pressure of all species after the system has reached equilibrium assuming that the temperature is 25.0 If the temperature is decreased...

  • Consider the following reaction: I2(g)+Cl2(g)⇌2ICl(g), Kp=81.9 (at 25∘C) A reaction mixture at 25∘C initially contains PI2...

    Consider the following reaction: I2(g)+Cl2(g)⇌2ICl(g), Kp=81.9 (at 25∘C) A reaction mixture at 25∘C initially contains PI2 = 0.110 atm , PCl2 = 0.110 atm , and PICl = 0.00 atm. Find the equilibrium partial pressure of I2 at this temperature. Find the equilibrium partial pressure of Cl2 at this temperature. Find the equilibrium partial pressure of ICl at this temperature.

  • problem #9 Calculate the equilibrium constant for the following reaction at 25°C. 2H2(g) + O2(g) 2H20cv)...

    problem #9 Calculate the equilibrium constant for the following reaction at 25°C. 2H2(g) + O2(g) 2H20cv) Given the following standard free-energy: H2O , -237.2 KJ/mol at 25°C. Problem #10. Given the following data at 25°C: substance sº (J/mol.K) AH', (KJ/mol) 240.45, 33.8 304.33 9.66 NO 249) N2O160) (a) Calculate the value of A Gº for the following reaction at 25°C: 2 NO2(9) N20 (9) (b) Is the formation of NO a spontaneous process at 25°C and standard-state conditions? (a) What...

  • I keep getting the answer for total pressure incorrect? Three glass bulbs, joined by closed stopcocks,...

    I keep getting the answer for total pressure incorrect? Three glass bulbs, joined by closed stopcocks, have the following volumes and initial pressures of the specified gases. Bulb A: 200. mL of CO2(g) at 570. torr Bulb B: 400. mL of Kr(g) at 0.500 atm Bulb C: 1.00 L of H2(9) at 101.325 kPa After both stopcocks are opened and the gases allowed to diffuse throughout, what will be the final total pressure? Ptotal- 1pts Submit Answer Incorrect. Tries 2/5...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT