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For calculations, assume Density of HCI = 1.0 g/mL Cs of soin = 4.184 / (ec) Calorimetry PART A. Determination of the Calorim
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Answer #1

From the given data ,

Density of water = 1g/ml

Mass/volume = 1g/ml

Mass/50ml = 1g/ml

Mass = 50ml×1g/ml

Mass = 50g

So,

Mass of water = 50g

Step (1) Calculation for haat of hot water.

m​​​​​​hw = 50g

Specific heat of water

C​​​​​​S(H2O) = 4.184J/g°C

Change in temperature

∆Thw = -25.4°C

Putting the all value in given formula

q​​​​​hw = mhwCs(H2O)∆Thw

q​​​​​hw = (50g)(4.184J/g°C)(-25.4°C)

q​​​​​​hw = 5313.68J

Step(2) Calculation for Heat of cold water.

m​​​​​cw = 50g

Specific heat

C​​​​​​S(H2O) = 4.184J/g°C

Change in temperature

∆Tcw = 17.7°C

Putting the all value in given formula

q​​​​​​​​​​​​Cw = mcwCs(H2O)∆Tcw

q​​​​​​cw = (50g)(4.184J/g°C)(17.7°C)

q​​​​​​cw = 3702.84J

Step(3) Calculation for heat of calorimeter

Putting the all value in given formula

q​​​​​​hw + q​​​​​qw + q​​​​​​cal = 0

-5313.68J + 3702.84J + q​​​​​​cal = 0

-1610.84J + q​​​​​​cal = 0

q​​​​​​cal = 1610.84J

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