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pore waters corespunucu 34. Balance the following oxidation-reduction reactions: PbO2 (s) → Pb2+ + O2 Fe2+ + MnO2 (6) Fe3+ +
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Ans 34 :

To balance the redox reactions, we start by writing the oxidation and reduction half reactions seperately. Then we balance all atoms other than hydrogen and oxygen .

Then oxygen and hydrogen is balanced by adding water molecules and protons respectively.

Charges are balanced by adding electrons.

Half reactions are added and simplified to get the balanced redox reactions as :

2PbO2 + 4H+ = 2Pb2+ + O2 + 2H2O

2Fe2+ + MnO2 + 4H+ = 2Fe3+ + Mn2+ + 2H2O

As2S3 + 5NO3- + 3H2O = 2HAsO42- + 3So + 5NO2- + 4H+

10CH2O + 8NO3- + 3H+= 4N2 + 5HCO3- + 5CO2 + 9H2O

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