Ka=7.2*10^-4
What is the pH at the equivalence point in the titration of a 28.7 ml. sample of a 0.314 M aqueous hydrofluoric acid solution with a 0.342 M aqueous barium hydroxide solution?
HF + Ba(OH)2----> BaF2 + H2O
0.314M. 0.342 M
0. 0.28 M 0.314 M
Finally we get mixture of two bases, so we will calculate pH from strong base Ba(OH)2 here.
Conc. of OH- = 2×0.28=0.56
pOH = -log 0.56 = 0.252
pH= 14-0.252= 13.748
What is the pH at the equivalence point in the titration of a 28.7 ml. sample of a 0.314 M aqueous hydrofluoric acid solution with a 0.342 M aqueous barium hydroxide solution
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