Question

6. I have a 2kg bal with a radius of 7m a. What is the moment of inertia of the bai? b. If I apply a force of 5 N to the edge of the ball at an angle of 80, what is the torque that is applied? c. For part c. What is the angular acceleration this will result in? If this acceleration contnues for 10 seconds, what will the velocity of the ball be? If this acceleration consnues for 10 seconds, how far wil the bal rol inearty?

Answer 1

Moment of Inertia = 2/5 M R^2 = 2/5 times 2 times 7^2 = 0.392 kg m^2 z = r^vector times F^vector = Fr sin theta = 5 times 7 sin 80 degree = 3.45 m alpha = I/I = 8.79 rad/s^2 w = alpha t = 8.79 times 10 = 87.9 rad/s v = r w = 0.7 times 87.9 = 61.55 m /s^2 Linear acc = a T alpha = 7 times 879 = 6.15 m/s^2 S = 1/ 2 at^2 = 1 /2 times 6.15 times 100 = 507.65 m