Y = 2X
For X = 1, 2, 3 Y = 2, 4, 8
Thus, the PMF of Y is,
P(Y = 2 ) = 0.3
P(Y = 4 ) = 0.5
P(Y = 8 ) = 0.2
E[Y] = 0.3 * 2 + 0.5 * 4 + 0.2 * 8 = 4.2
E[Y2] = 0.3 * 22 + 0.5 * 42 + 0.2 * 82 = 22
Var[Y] = E[Y2] - (E[Y])2 = 22 - 4.22 = 4.36
Z = aX + b
E[X] = 0.3 * 1 + 0.5 * 2 + 0.2 * 3 = 1.9
E[X] = 0.3 * 12 + 0.5 * 22 + 0.2 * 32 = 4.1
Var[Y] = E[Y2] - (E[Y])2 = 4.1 - 1.92 = 0.49
E[Z] = 0
=> E[aX + b] = 0
=> aE[X] + b = 0
=> 1.9a + b = 0 ---(1)
Var[Z] = 1
=> Var[aX + b] = 1
=> a2Var[X] + Var[b] = 1
=> a2Var[X] + 0 = 1
=> 0.49a2 = 1
=> a2 = 1/0.49
=> |a| = 1/0.7 = 10 / 7 = 1.428571
From (1),
1.9a + b = 0
=> b = -1.9 a
=> |b| = 1.9 |a|
=> |b| = 1.9 * 1.428571 = 2.714285
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