Question

Chapter 22, Problem 008 In the figure the four particles are fixed in place and have charges q,-q2-3e, q3 = 2e, and q4--8e. Distance d = 5.82 μm, what is the magnitude of the net electric field at point P due to the particles? 1 93 42

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Answer #1

Field due to q1 and q2 is cancelled because of symmetry.

Net electric field E = kq3/d^2 + kq4/[2d]^2

= k*2e/d^2 + k*-8e/4d^2

= 0 Answer

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