Please check my answers to part a and b, an help me answer part c. I am not sure if I set it up correctly. Show work please, thank you.
Please check my answers to part a and b, an help me answer part c. I...
PLEASE explain part (c) clearly with detailed steps...I know the answer is 19 mL 6. A chemist starts her experiments with 25.00 mL of 0.125 mol L + NaCN solution. The pKof HCN = 9.20. a) What volume of 0.100 mol + HCl will be required to fully react with the above salt? b) After the reaction in part a) takes places, will the pH of the solution be acidic, basic or neutral? c) What volume of 0.100 mol L?HCl...
The answer to part A was found to be pH=4.19. Now i just need help on parts B and C What is the pH of a buffer solution containing 0.02 M KHSO4 and 0.01M H2SO4 (Ka1.3 x 104)? (a) (b) what is the percentage (%) of conjugate base that was hydrolyzed for each reaction in Problem 2? (c) What is the pH of the 0.02M KHSO4 and 0.01M H2SO4 buffer solution after adding 0.05 M HCI? What is the pH...
please help walk me through how to solve these, the questions change everytime. i am not even sure where to start. thank you HON WILL UNULNEM TULENERAL CHEMISTRY LABE Amber Gloria's Qula History Lab & Quiz Exploring Buffers Background Incorrect Question 3 0/1 pts If you mix a weak acid and a weak base together with concentrations of 0.33 and the acid has apk, -8.58, what is the pH of the buffer? Give your answer to two decimals. pH =...
Hey guys, I am having a lot of trouble with my homework. Could you please help? I thumbs up anyone who gives a thorough explanation and shows the work! I really need to understand these concepts! Thank you guys! 1) The Ka for HCN is 4.9 ~ 10-10. What is the value of Kb for CN-? 2) Using the data in the table for 0.10 M aqueous species at 25 °C, which conjugate base below is the weakest base? Explain...
Hey guys, I am having a lot of trouble with my homework. Could you please help? I thumbs up anyone who gives a thorough explanation and shows the work! I really need to understand these concepts! Thanks in advance! 1) The Ka for HCN is 4.9 ~ 10-10. What is the value of Kb for CN-? 2) Using the data in the table for 0.10 M aqueous species at 25 °C, which conjugate base below is the weakest base? Explain...
Hey guys, I am having a lot of trouble with my homework. Could you please help? I thumbs up anyone who gives a thorough explanation and shows the work! I really need to understand these concepts! Thank you! 1) The Ka for HCN is 4.9 ~ 10-10. What is the value of Kb for CN-? 2) Using the data in the table for 0.10 M aqueous species at 25 °C, which conjugate base below is the weakest base? Explain your...
Can you please answer the part i underlined? Thanks!! Point A,b,c is not given details about the points are given so you have to guess and find it thats the part I was having a hard time with Computer-Simulated Titration Curve 12.00 + 0.00 10.00 0.00 12.00 2.00 8.00 4.00 6.00 Drops of Added 0.01 M NaOH Figure 14.10 1 drop of 0.04 M H,PO, with 0.01 M NaOH. H3PO4(aq) + NaOH(aq) + NaH PO,(aq) + H2O(1) Referring to Figure...
I really need help on how to find out the answers for part a, b,c... Can I get help please? 10. Classify the following solutes represented in each of the following equations as either a strong electrolyte, a weak electrolyte, or a nonelectrolyte. (3 points) H2O a) C12H22011 () C12Hz2011 (aq) none b) K2SO4(s) H2O → K(aq) + SO42- (aq) strong c) H3PO4 (aq) H2O = + H2PO4 (aq) + H+ (aq) weak
hi! can you please help me figure out part C and D please? I re-did my work on part A, but don't know how to do part C and D. Thank you so much :) H23 - 1.00794 (2) + 32.066 = 34.08188 Alz S3 > 26.981538 (2) + 32.066(3) = 150.161076 PART II: PROBLEMS: Give a complete solution to each problem. SHOW YOUR WORK! Follow proper procedures concerning units and sig figs. Point values given. 6. Consider this unbalanced...
please answer all parts part 1 part 2 (c) part 3 Designate the Bronsted-Lowry acid and the Bronsted-Lowry base on the left side of each equation, and also designate the conjugate acid and conjugate base on the right side. (a) H2O(0) + HPO 2(aq) = OH(aq) + H2PO4 (aq) H2O OB-L acid B-L base conj. acid conj. base HPO, 2- OB-Lacid B-L base conj. acid con base он B-L add B-L base conj, acid conj, base НРО B-L acid B-L...