1)Null hypothesis H0 :
2) Alternative Hypothesis H1 :
3) level of significance = 0.05
4) decision rule
If test statistic is greater than critical value t/2,n-1 we reject null hypothesis otherwise fail to reject H0.
5) test statiostic
given n=36
mean M = 29.86
std dev s = 3.87
t = = -0.217
degrees of freedom = n-1 = 36 - 1 = 35
critical value = t0.025,35 = 2.030
6) Since |t| < t0.025,35 we fail to reject null hypothesis and there is no significant evidence to conclude that the average number of raisins per box is different from expected 30.
how do i solve all six steps? As quality control manager at a raisin manufacturing and...
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