Question

Two moles of gas initially at a pressure of 2.00 atm and a volume of 0.300 L has Internal energy equal to 10). In tha Intemal energy equals 182). P(alm) My Notes Ask Your Teacher a pressure of 1.50 tm and volume of 0.00 L, and its t , the gas is 200 1.50-AL 0.500 0.800" hers) (a) For the paths IAF, IBF, and IF in the figure above, calculate the work done on the gas. WAR - -76.0 Wrap -101 - HÀ (b) For the paths IAF, IBF, and if in the figure above, calculate the net energy transferred to the gas by heat in the p Qur -1013 Double check your The response you submitted has the wrong sign. ) 91 X 10 Your response differs from the correct answer by more than 10% Q .538.93 X Your response differs from the correct answer by more than 100% Need Help? Read it

Answer 1

Great work on part (a) !!!!

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(b) we need to use first law of thermodynamics

$\Delta$U = Q + W

notice that $\Delta$U (change in internal energy) = 182 - 91 = 91 J

so,

Q_IAF =  $\Delta$U - W

Q_IAF = 91 + 76

Q_IAF = 167 J

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Q_IBF = 91 + 101 = 192 J

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Q_IF = 91 + 88.63 ( THIS ANSWER OF YOURS WAS NOT CLEAR DUE TO BLURRED IMAGE)

Q_IF = 179.63 J