Question

Review Part A A parallel-plate capacitor is formed from two 2.8 cm -diameter electrodes spaced 3.0 mm apart. The electric field strength inside the capacitor is 6.0 × 106 N/C What is the charge (in nC) on each electrode? Express your answer using two significant figures. You may want to review (Pages 644 645) nC Submit Request Answer

Answer 1

answer) we know the formula

E=Q/$\varepsilon$_oA

A=0.028*0.028=7.84*10^-4m²

Q=$\varepsilon$_oAE=8.85*10^-12*6*10⁶N/C*7.84*10^-4m²=4.163*10^-8C=42nC

so the answer is 42nC