The K, of a weak monoprotic acid is 1.59 x 10-, What is the pH of...

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Answer 1

Answer #1

Date II Page Let HX Be the mono protts acid Hх – н+ + + 0:0913 1 + ka = [H+] [x- IHY] - J . (0.0913-x) 1.59x10-5 = x2 (0.091

Answer 2

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