Question

6. In a particular kind of steel (one of the Standard 300 series austentic grades, for you steel-heads), the composition by mass is roughly 0.15% C, 1.00% Si, 2.00% Mn, 0.045% P, 0.030% S, 17.00% Cr, 7.00% Ni, and the rest Fe. What is the ratio of iron atoms to carbon atoms in this steel? Please use integer numbers for your ratio (for example, 7:4.)

Answer 1

% of C = 0.15 yo si = 1.00% 1. of Mn = 2.0%. y of P = 0.0457. Y. og 5 = 0.0307. & cv = 17007. 2. Nie 7.00y. y. Fe = 100- (0.15 + 1100 +2.00 + 0.045 +0.030 +17+7) = 72.775% For 15og stree Mas as c = 0.15 5 no of holes of t= 0.15 mole 12.01 noi o atoms of t= 0.15 x 6.0R2 x 23 12.01 utoms Mass Re- 72.7757 no. of moles of Fe= 72.775 55.845 no. of atoms I Fe= 72.775 61022x10 55.45 Ratio Te aton - 72.775 6.022XTOP3 55.845 * Carbon aton 3.15 & 6.022X123 12.01 = 72.775 x 12.01 - 10413 55.845 0.15 Ans ratio= 104.3 10.775 mole