Question

19. 1/2 points Previous Answers My Note: A common technique for accelerating electons is to create a uniform electric field between two plates, as shown in the figure below. Electrons are released, usually from a hot lament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to continue moving. a calculate the acceleration of the electron if the field strength is 8.12 X 100 NC. Alculate the force from an electric held on a point charge? How does this relate to Newton's second law? What is the mass of an electron m/s (D) Why will the electron not be pulled back to the positive plate once it moves through the hole? The force of gravity is too strong, o There is no field outside the plates. The other side of the positive plate also has a negative charge.

Answer 1

2 Sol: According to the question, The field strength between the two plates is. E= 8.12 x 104 N/C. Charge of an electreon, q= 1.6x10-19 c. Mas of an election, m= 9.1 x 10-31 kg Let a be the acceleration of the electreon. So, the forece on the electreon, I = QE on ma = qe Or a = QE m ove, a = 1.681019 x 8.12 x 104. g. lx 10-31 ore, a = 1042 x 1016 m/s² 1 1 + 1 + 1 + 1 + + So, the acceleration of the electron is 1.42 x 1016 m/s² (6 The electreon positive plate • Theree is will not be pulled back to the once it moves through the hole because, no field outside the plates.