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Fill in the Blanks A 27.0 g sample of an unknown hydrocarbon was burned in excess oxygen to form 88.0 g of carbon dioxide and
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Answer #1

Moles of Carbon dioxide ( CO2 ) = weight in gm / molar mass = 88 gm / 44 gm mol—1 = 2 mol

moles of H2O = 27 gm / 18 gm mol—1 = 1.5 mol

moles of carbon = moles of CO2 = 2mol

moles of Hydrogen = 2 x moles of H2O = 2 x 1.5 = 3 mol

C atoms = 2

H atoms = 3

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