The balanced chemical equation for the reaction between carbon disulfide and chlorine is: CS2(s) + 4C12(e)...
When carbon disulfide reacts with chlorine, carbon tetrachloride and sulfur dichloride are produced. The balanced equation for this reaction is: CS2(s)+ 4C12 (8) CC4()+2SCI (s) If 16 moles of chlorine react, The reaction consumes moles of carbon disulfide. The reaction produces moles of carbon tetrachloride and moles of sulfur dichloride.
Interpret the following equation for a chemical reaction using the coefficients given: CO(g) + Cl2(g) - COC12(g) On the particulate level: of CO(g) reacts with of Cl2(g) to form of COC12(g). On the molar level: of CO(g) reacts with of Cl2(g) to form of COCIz(g) The balanced chemical equation for the reaction between carbon disulfide and chlorine is: CS(s) + 4Cl2() CCI (1) +2 SCI2 (8) We can interpret this to mean: 4 moles of chlorine and mole(s) of carbon...
For the following reaction, 23.9 grams of carbon disulfide are allowed to react with 92.4 grams of chlorine gas carbon disulfide(s) + chlorine(g) >carbon tetrachloride(1) + sulfur dichloride(s) What is the maximum amount of carbon tetrachloride that can be formed? grams What is the FORMULA for the limiting reagent? What amount of the excess reagent remains after the reaction is complete?
Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is S2 (g)+ C(s) -->CS2 (g) Kc = 9.40 at 900K How many grams of CS2(g) can be prepared by heating 15.5 moles of S2(g) with excess carbon in a 8.15 L reaction vessel held at 900 K until equilibrium is attained?
Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is How many grams of CS2(g) can be prepared by heating 10.8 moles of S2(g) with excess carbon in a 5.30 L reaction vessel held at 900 K until equilibrium is attained? rbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is 9.40 at 900 K CS How many grams of g) can be prepared by heating 10.8 moles of S2(g) with excess carbon in...
Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is S2(g)+C(s)−⇀↽−CS2(g)Kc=9.40 at 900 KS2(g)+C(s)↽−−⇀CS2(g)Kc=9.40 at 900 K How many grams of CS2(g)CS2(g) can be prepared by heating 12.6 mol S2(g)12.6 mol S2(g) with excess carbon in a 6.70 L6.70 L reaction vessel held at 900 K until equilibrium is attained? mass of CS2(g)
points Carbon disulfide and chlorine react according to the following equation: CS2(g) + 3C12() SC12(Ⓡ) + CC446) When 1.14 mol of CS2 and 4.80 mol of Cl2 are placed in a 2.00-L container and allowed to come to equilibrium, the mixture is found to contain 0.650 mol of CC14. How many moles of Cl2 are present at equilibrium? a. 0.490 mol b. 3.50 mol OC 0.650 mol d. 1.43 mol e. 2.85 mol
Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is S,(g) + C(s) = CS, (g) Kc = 9.40 at 900 K How many grams of CS2(g) can be prepared by heating 11.8 mol S2(g) with excess carbon in a 6.15 L reaction vessel held at 900 K until equilibrium is attained? mass of CS2(g): 09
The Raptors According to the following reaction, how many grams of carbon tetrachloride will be formed upon the complete reaction of 27.4 grams of chlorine gas with excess carbon disulfide? carbon disulfide (1) chlorine (@) - karbon tetrachloride (1) + sulfur dichloride (s) prams carbon tetrachloride
Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is S2(g) + C(s) = CS, (g) Kc = 9.40 at 900 K How many grams of CS2(g) can be prepared by heating 11.4 mol S2(g) with excess carbon in a 5.15 L reaction vessel held at 900 K until equilibrium is attained? mass of CS2(g): bun