Answer
pH = 2.80
Explanation
Stepwise neutralisation reaction is
H2A + OH- ------> HA- + H2O pKa1 = 2.80
HA- + OH- ------> A2- + H2O pKa2 = 6.50
at one quarter neutralization , diprotic acid presents are H2A , HA-
[H2A]= [HA-]
Henderson - Hasselbalch equation is
pH = pKa + log([A-]/[HA])
pH = 2.80 + log(1)
pH = 2.80
Part E A diprotic acid has a pKa, 2.80 and pka2 6.50. What is the pH...
Part E A diprotic acid has a pKa1 -2.80 and pka2 6.50. What is the pH of a 0.10 M solution of this acid that has been one quarter neutralized? 97 ΑΣΦ Submit Request Answer Part E A diprotic acid has a pKa1 -2.80 and pka2 6.50. What is the pH of a 0.10 M solution of this acid that has been one quarter neutralized? 97 ΑΣΦ Submit Request Answer
home / study / science / chemistry / chemistry questions and answers / a diprotic acid has a pka1 = 2.90 and pka2 = 6.50. what is the ph of a 0.10 m solution of ... Question: A diprotic acid has a pKa1 = 2.90 and pka2 = 6.50. What is the pH of a 0.10 M solution of this a... A diprotic acid has a pKa1 = 2.90 and pka2 = 6.50. What is the pH of a 0.10...
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