Question

Calculate the pH when 200.0 mL of a 1.00 M solution of H2A (Ka1 = 1.0 x 10–6, Ka2 = 1.0 x 10–10) is titrated with the following volumes of 1.00 M NaOH. 250.0 mL of 1.00 M NaOH Group of answer choices

Answer 1

The Balanced Equaton is Inaoht HogA NORA +H2O ginen mole of HgA = MAU=1.0 molx 0.2 L = 0.291 mele of NaoH added a on molx 0.250 L = 0.250 ml for Iss Equivalent point H₂A + OH 0.2 0.25 no.2 -0.2 - 0 1 C HAO + Hoo - +0.2 0 secand Equivalent point HAO q) + alte aa) - A-rac) + H2O I 0.2 0.05. to..5 E 0.15o 05 H40 YAZ HAO and A-2 fact of buores Solution

and kag - 1.0x1ol, pla q = - lug (kaz) = log (1.0x/0-10) - 10.0 Hendr -San Equation for pH pH = pla Hog CA 2] (HA) = 10 + logo = lo+log (6.893) a 10+(-0.477) = 9.52 plet of solutar = 9.52