Question

I need help with the following procedure

Determine tL Mess af KIO and Naz So3 needed to Make Stoc Solution 250 ML KIO,ineed hmber of grams to hale ofe oianoM KTo Salutlon Nan SOained number of grams to ake Soo ML at O0025M Solutlon Describe how prepare 20.00ML O0050 MKI 9, 5alution fron stocl Solutian with of a Concantratlon of o,b2.0M rearent in ths reachlon whet is the Limiti

Answer 1

volume = 250mL = 0.250L Molarity = 0.0209 moles of klo, = 0.020 X0-250 0.0050 mol mass of kille = 0.0050x 214 1072 1.079. The A moles of Na, so = 500 x 0:0025. 1000 = 1.25x10 mo! mass of Na₂SO₃ = 1.25x103 x 126 - 0.1582 20.00 X 0.0050 = 0.0204 V-5ML volume of stock solution = 5.0mL take 5 mL stock solutron and add 15.0 me ater to it to prepare 20.0 m2 solution . limiting reagent is Na₂SO3. because no. of moles of Na, so is less -