4. Which of the following transitions of an electron in a hydrogen atom corresponds to the lowest frequency of the emitted photon? (n = 2 → n = 10 means a transition from the state with n = 2 to the state with n = 10)
(A) n = 4 → n = 2
(B) n = 5 → n = 3
(C) n = 4 → n = 5
(D) n = 6 → n = 3
(E) n = 5 → n = 2
For emission, electron moves from higher energy state to lower energy state.
So, C is not emission.
For lowest frequency, energy difference between value of n should be lowest.
Since as value of n increases, energy difference between subsequent shell decreases, so energy difference will be minimum in case of B
So, B would have lowest frequency
Answer: B
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