CH4(g) + 2O2(g) ---------> CO2(g) + 2H2O(l) H = -890.4KJ --------------> 1
C (s) + O2(g) -------------> CO2(g) H = -393.5Kj ---------------->2
2C(s) + O2(g) ----------> 2CO(g) H = -221.0KJ ------------> 3
adding equation 2 and 3
C (s) + O2(g) -------------> CO2(g) H = -393.5Kj ---------------->2
2C(s) + O2(g) ----------> 2CO(g) H = -221.0KJ ------------> 3
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3C(s) + 2O2(g) ------------> CO2(g) + 2CO(g) H =- 614.5Kj ----------------> 5
subtract equation 5 and 1
3C(s) + 2O2(g) ------------> CO2(g) + 2CO(g) H =- 614.5Kj ----------------> 5
CH4(g) + 2O2(g) ---------> CO2(g) + 2H2O(l) H = -890.4KJ --------------> 1
(-) (-) (-) (-) (+)
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3C(s) + 2H2O(l) ------------> CH4(g) + 2CO(g) H = 275.9KJ >>>>>answer
Consider following chemical reactions: 1) CH2(g) + 2O2(g) → CO2(g) + 2H20(1) 2) C(s) + O2(g)...
please help Consider following chemical reactions: 1) CH.(g) + 2O2(g) → CO2(g) + 2H2O(1) 2) C(s) + O2(g) → CO2(g) 3) 2C(s) + O2(g) - 200(g) 4) 3C(s) + 2H2O) CH4(g) + 2COg) H2O(l) indicates that H20 is in liquid state. If the Enthalpy of reaction for reaction 1, 2, and 3 are -890.4kj, -393.5kj and - 221.Okj respectively; try to figure out the Enthalpy of reaction for reaction 4. Please show your work.
Consider following chemical reactions: 1) CH2(g) + 202(g) → CO2(g) + 2H20(1) 2) C(s) + O2(g) → CO2(g) 3) 2C(s) + O2(g) → 2C0(9) 4) 3C(s) + 2H2O(l) → CH4(g) + 2CO(g) H2O(l) indicates that H2O is in liquid state. If the Enthalpy of reaction for reaction 1, 2, and 3 are -890.4kj, -393.5kj and -221.0kj respectively; try to figure out the Enthalpy of reaction for reaction 4. Please show your work.
Consider following chemical reactions: 1) CHa(g) +202(8)-CO2(g) 2H20() 2) C(s) O2(g) CO2(g) 3) 2C(s)O2(g) 2CO(g) 4) 3C(s) 2H20()CH4(g)2CO(g) H2O(I) indicates that H2O is in liquid state. If the Enthalpy of reaction for reaction 1, 2, and 3 are -890.4kj, -393.5kj and -221.0kj respectively; try to figure out the Enthalpy of reaction for reaction 4. Please show your work.
Calculate ΔrH for the following reaction: CH4(g)+2O2(g)→CO2(g)+2H2O(l) Use the following reactions and given ΔrH's. CH4(g)+O2(g)→CH2O(g)+H2O(g), ΔrH = -284 kJmol−1 CH2O(g)+O2(g)→CO2(g)+H2O(g), ΔrH = -527 kJmol−1 H2O(l)→H2O(g), ΔrH = 44.0 kJmol−1
Use the example shown to calculate the reaction enthalpy, delta H, for the following reaction: CH4(g)+2O2(g)->CO2(g)2H2O(l). Use the series of reaction that follows: 1. C(s)+2H2(g)-> CH4(g), delta H= -74.8 kJ 2. C(s)+O2(g)->CO2(g), delta H= -393.5 kJ 3. 2H2(g)+O2(g)-> 2H2O(g), delta H= -484.0 kJ 4. H2O(l)->H2O(g), delta H= 44.0 kJ
Calculate the enthalpy of the following reaction: C (s) + 2 H2 (g) --> CH4 (g) Given: C (s) + O2 (g) --> CO2 ΔH = -393 kJ H2 + 1⁄2O2 --> H2O. ΔH = -286 kJ CH4 + 2O2 --> CO2 + 2H2O ΔH = -892 kJ
Given the following equilibrium equations and their corresponding equilibrium constants: 2CO2 (g)+H2O(g)⇌2O2 (g)+CH2CO(g) Kc=6.1x108 CH4(g)+2O2(g)⇌CO2 (g)+2H2O(g) Kc=1.2x1014 Find Kc for the reaction: CH4(g) + CO2(g) ⇌ CH2CO (g) + H2O (g) 2 of 5 .. .........e following equilibrium equations and their corresponding equilibrium constants: 2 CO2 (g) + H20 (g) – 202 (g) + CH2CO (g) Kc = 6.1 x 108 CH2(g) + 2 O2(g) - CO2 (g) + 2 H2O(g) Kc = 1.2 x 1014 Find Kc for the...
Consider the four reactions listed below for the next question. 1. FeO(s)+CO(g)<->Fe(s)+Co2(g) K=0.403 2. 2C(s)+O2(g)<->2CO(g) K=1x10at16 power 3. 2Cl2(g)+2H2O(l)<->4HCl(aq)+O2(g) K=1.9x10 at-15 power 4. C(s)+2H2(g)<->CH4(g) K=27.5 a.Which reaction has the smallest tendency to occur? 1. Reaction a 2. Reaction b 3. Reaction c 4. Reaction d
What is AHin for the following chemical reaction? CS2(g) + 2H20(1) - CO2(g) + 2H2S(g) You can use the following table of standard heats of formation (AH) to calculate the enthalpy of the given reaction Element Compound Element Compound Standard Heat of Formation (kJ/mol) 218 Standard Heat of Formation (kJ/mo!) 473 0 285.8 H(g) H2(g) H2O(1) CS2(g) C(g) C(s) N(8) 02 (8) 0(g) H2S(g) CO2(g) HNO3(aq) 116.7 249 20.60kJ 393.5kJ 206.6 Express the standard enthalpy of reaction to three significant...
Please explain Data: C(graphite) + O2(g) => CO2(g) AH = -393.5 kJ H2(g) + 1/2O2(g) => H2O(1) AH = -285.8 kJ CH3OH(1) + 3/202(9) A CO2(g) + 2H20(1) AH = -726.4 kJ Using the data above, calculate the enthalpy change for the reaction below. Reaction: C(graphite) + 2H2(g) + 1/2O2(g) => CH3OH(1) A. +238.7 kJ B.-238.7 kJ C. +548.3 kJ D.-548.3 kJ E. +904.5 kJ