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4. Consider a horizontal tube filled with air which is closed at one end. By blowing across the open end the fundamental standing wave of the air column inside the tube is produced. [You can assume the speed of sound in air is 344ms-1] (a) Sketch the tube, clearly labelling all of the pressure and displacement nodes (b) If the length of the air column in the tube is 32.0 cm, calculate the frequency and anti-nodes of this standing wave and the closest higher harmonic. The closed end of the tube is now opened. (c) Sketch the tube again, labelling the new positions of the (i) pressure and (ii) displacement nodes and anti-nodes for the fundamental frequency. Specify the new fundamental frequency (d) If a fine uniform layer of powder is now added along to the bottom of the tube, specify where will the powder tend to move to under the influence of the wave vibrations. Explain your reasoning 10] OVK, 2019Help please with full explanation. For like and comment.

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In closed end organ pipe, fundamental standing wave is having one fourth of wavelength

GL Poe&s wro lod.e AT No. (», placement Speed saund 3VwH far fumdamanstah wave, n 128 cm 123 C 12孑 closest hithee free3m 806.2 S Hz Node 4 Cc) 3537. S H2 6 y(d) particals of powder will tend to collect at the middle of the pipe, means at point of Node

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