Question

Four particles sit on the corners of a square with sides of length d -2.50 mm and have charges of q1 +g, q2 =-2q, q3 +3g, and q4 =-4q. Charge q1 sits in the top left corner and the remaining charges are placed in order clockwise around the square. What is the magnitude of the electric force on a fifth charge q5 = +5q placed at the middle of the square if q = 3.00 nC? 810

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Answer #1

The arrangement is shown below The separation between center and corner charge is 2 2 2.50x10-3 -1.77x10-3 m The forces are ka(54) (9x10%)(5)(3x10-9)2 (1.77x10) -0.13 Nka2g5 (-2g)5g) 9-10)1 -10)(3-10) 1.77x103 -0.26 N 1 k(3q) (5q) (9x10)(15)(3x10) 1.77x10-3 -0.39 N ka.qs (g5g) 9x10 )(-20)(3x109 1.77x103 0.52 N The x component of net force is Fcos45+ F cos 45 + F cos 45- Fcos 45 -(-F+F+F -F) cos 45 (-0.13+0.26+0.39-0.52)cos 45 The y component of net force is F, -Fsin45-F sin 45 + Fj sin 45 + F^sin 45 -(--F+F+F)sin45 - (-0.13-0.26+0.39+0.52 sin 45 0.37 N The magnitude of force is- V00.372

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