Determine the mass of 68.1% Na3PO4 solution that contains 9.26 g of Na+.
Answer: _____g solution
Molar mass of Na = 22.99 g/mol
mass(Na)= 9.26 g
use:
number of mol of Na,
n = mass of Na/molar mass of Na
=(9.26 g)/(22.99 g/mol)
= 0.4028 mol
This is number of moles of Na
one mole of Na3PO4 contains 3 mole of Na
use:
number of moles of Na3PO4 = number of moles of Na3PO4 / 3
= 0.4028 / 3
= 0.1343
Molar mass of Na3PO4,
MM = 3*MM(Na) + 1*MM(P) + 4*MM(O)
= 3*22.99 + 1*30.97 + 4*16.0
= 163.94 g/mol
use:
mass of Na3PO4,
m = number of mol * molar mass
= 0.1343 mol * 1.639*10^2 g/mol
= 22.01 g
Now use:
Mass % of Na3PO4 = mass of Na3PO4 * 100 / mass of solution
68.1 = 22.01 * 100 / mass of solution
mass of solution = 32.3 g
Answer: 32.3 g
Determine the mass of 68.1% Na3PO4 solution that contains 9.26 g of Na+. Answer: _____g solution
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