answer is 1.66 assumption cannot be made because x is not small
x cannot be 0.042 because concentration at equilibrium will be negative of the reactant.
solve without using the quadratic formula What is the pH of a 0.030 M solution of...
Calculate the pH of a weak acid solution using the quadratic
formula. Please box answer! Thank you!
Close Problem Tutored Practice Problem 16.4.4 S O NDE Calculate the pH of a weak acid solution (quadratic equation). Calculate the pll of a 0.0322 M aqueous solution of nitrous acid (HINO), K-4.6x10") and the equilibrium concentrations of the weak acid and its conjugate base pH (HNO3Jequilibrium [NO2 loqulibrum Check Sem Arses Shopproach
What is the pH of a 0.030 M solution of weak acid HA for which Ka = 6.6 x 10-5?
6. What is the pH of a 2.75 x 10-6 M solution of HCI? 5.56 5.54 4.85 3.26 7. Consider the complexation reactions below: Zn2++C2O Zn2++2 C2022 ZnC20 Zn(C204)22 K1= 7.1 x 10 B1 4.0 x 107 If you mix 0.025 M Zn(NO3) with 0.030 M Na,C,O4, what is the mass balance C2O,2-? O 2IZN*] = 2 (C,0,2-1+2 [Zn(C,0,)2 0.030 = [C20,2- + [Zn(C204)] + [Zn (C,O4)22- [C20,2-1+Zn(C20,)] + 2 [Zn(C204)22-] 0.030 O None of the above. 8. Butanoic acid...
7. (a) Define pH (b) Calculate the pH of 0.030 M Ba(OH)2 solution (c) Calculate the pH of a solution containing 0.085 M nitrous acid alone and a solution containing 0.085 M nitrous acid and 0.10 M potassium nitrite (KNO2). K, for HNO2 = 4.5 x 10-
Calculate the [H+] and pH of a 0.000143 M butanoic acid solution. Keep in mind that the Ka of butanoic acid is 1.52 x10-5. this is a problem that will require you to use the quadratic. Start by setting up the quadratic equation before using the quadratic formula and find the coefficients. Then solve the quadratic. Quadratic formula:ax2+bx+c=0; enter the values of a, b, and c a= b= c= [H+]= M pH=
3. What is the approximate expected pH of a 0.030 M HNO, solution? What is the final pH after 1 drop (0.05 mL) of 6 M HCl is added to 1.0 L of freshly prepared pure water that was significant pH change? 4. pH of 7.0. Is there originally at a a What is the molarity of pure water at 20°C? 5. a. b. Does the concentration of water change significantly (from the value in 4-a) when enough acetic acid...
This Question: 14 pts Solve for x using the quadratic formula x2-5x-50-0 The solution is x Simplfy your answer. Type an exact answer, using radicals andi/as needed Use a comma to separate answers as needed
Calculate the pH and the equilibrium concentrations of HC2O4- and C2O42- in a 0.0782 M oxalic acid solution, H2C2O4 (aq). For H2C2O4, Ka1 = 5.9×10-2 and Ka2 = 6.4×10-5 pH =_______ [HC2O4-] =___________ M [C2O42-] =___________ M
Calculate the pH and the equilibrium concentrations of HC2O4- and C2O42- in a 0.1160 M oxalic acid solution, H2C2O4 (aq). For H2C2O4, Ka1 = 5.9×10-2 and Ka2 = 6.4×10-5 pH = [HC2O4-] = M [C2O42-] = M
Calculate the pH of 1.00 x 10^-2 M oxalic acid solution. Calculate the pH of 1 x 10^-2 M solution of sodium oxalate. Ka1 = 5.62 x 10^-2, Ka2 = 5.42 x 10^-5